Answer:
%Al = 34.6%
%0 = 61.5%
%H = 3.9%
Explanation:
Al(OH)3
Atomic mass of Aluminum Al = 27
Atomic mass of Oxygen O=16
Atomic mass of Hydrogen H=1
Molar mass of Al(OH)3 = 27 + (16*3) + (1*3)
Al(OH)3 = 27 + 48 + 3
Al(OH)3 = 78
Percentage composition;
Aluminum Al= (27/78) × 100
Aluminum Al=0.346 × 100 =34.6%
Oxygen O=(16*3/78) × 100
Oxygen O= 0.615 × 100 =61.5%
Hydrogen H= (1*3/78) × 100
Hydrogen H=0.039 × 100=3.9%
