if measure angle MPL=63 HOW COULD I FIND THE OTHERS?

answer:
JK = 27
NJ = 153
JL = 117
KNM = N/A
MJL = N/A
JLK = N/A
step-by-step explanation:
∠NPM + ∠MPL = 90
∠NPM + 63 = 90
∠NPM = 27°
so, ∠JPK = 27° (since they are vertical angles)
63 + 90 + 27 + 27 + X = 360
63 + 90 + 27 + 27 + X = 360
207 + X = 360
X = 153
so, ∠JPN = 153°
ARCS:
JK = 27
NJ = 153
JL = 117
KNM = N/A
MJL = N/A
JLK = N/A
- sorry this is the furthest i can help, i have only learnt up to that so do not know how to find the rest.
using the relationship between intercepted arc and central angle, the missing measures are:
a. m(JK) = 27°
b. m(NJ) = 153°
c. m(JL) = 117°
d. m(KNM) = 207°
e. m(MJL) = 297°
f. m(JLK) = 333°
Given:
m∠MPL = 63°
a. m(JK) = 180 - 90 - 63 = 27°
m(JK) = 27°
b. m(NJ) = 180 - m(JK)
m(NJ) = 180 - 27
m(NJ) = 153°
c. m(JL) = 90 + 27
m(JL) = 117°
d. m(KNM) = 180 + 27
m(KNM) = 207°
e. m(MJL) = 27 + 180 + 90 = 297°
f. m(JLK) = 360 - 27
m(JLK) = 333°
Therefore, using the relationship between intercepted arc and central angle, the missing measures are:
a. m(JK) = 27°
b. m(NJ) = 153°
c. m(JL) = 117°
d. m(KNM) = 207°
e. m(MJL) = 297°
f. m(JLK) = 333°
Learn more about central angles and intercepted arcs on:
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