olivialprescott olivialprescott
  • 17-03-2020
  • Mathematics
contestada

what is the inverse of cube root x/3 +1

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 25-03-2020

Answer:

[tex] {f}^{ - 1} (x) = 3 {x}^{2} - 3[/tex]

Step-by-step explanation:

We want to find the inverse of

[tex] y = \sqrt[3]{ \frac{x}{3} + 1} [/tex]

We interchange x and y to get:

[tex]x= \sqrt[3]{ \frac{y}{3} + 1} [/tex]

We solve for y;

[tex] {x}^{2} = \frac{y}{3} + 1[/tex]

Multiply through by 3

[tex]3 {x}^{2} = y + 3[/tex]

Subtract 1 from both sides:

[tex]y = 3 {x}^{2} - 3[/tex]

Therefore the inverse is

[tex] {f}^{ - 1} (x) = 3 {x}^{2} - 3[/tex]

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