Question

if 95 grams of iron are needed to react with sulfur, how many grams of sulfur are involved

Answer 1

i would say 190 grams

Answer 2

Answer:

54.48g of S

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

Fe + S —> FeS

Molar Mass of Fe = 55.8g/mol

Molar Mass of S = 32g/mol

From the equation,

55.8g of Fe required with 32g of S.

Therefore 95g of Fe will require = (95 x 32)/55.8 = 54.48g of S