Respuesta :
Answer:
1.44 s
Explanation:
Since it is a projectile motion, we use the formula for the total time of flight,t
t = 2Usinθ/g where U = initial velocity of ball = 10 m/s, θ = 45 and g = 9.8 m/s²
t = 2Usinθ/g = 2 × 10sin45/9.8 = 1.44 s
So, the time needed for the ball to return to the ground is most nearly: 1.44 s
We have that for the Question it can be said that the time needed for the ball to return to the ground is most nearly
T=1.44
From the question we are told
A ball is thrown into the air with an initial velocity of 10 m/s at an angle of 45 degrees above the horizontal, as represented above. If air resistance is negligible the time needed for the ball to return to the ground is most nearly
Generally the Newton's equation for the vertical displacement is mathematically given as
[tex]y=ut+1/2at^2\\\\Therefore\\\\T=\frac{2Usin\theta}{g}\\\\T=\frac{2*10*sin45}{9.8}\\\\[/tex]
T=1.44
Therefore
the time needed for the ball to return to the ground is most nearly
T=1.44
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