Answer:
The value of the partial pressure of the oxygen [tex]P_{O_{2} }[/tex] = 690 torr
Explanation:
Total pressure of the mixture of gases = 736 torr
The partial pressure of water vapor = 46 torr
From the law of pressure we know that
Total pressure = The partial pressure of water vapor + The partial pressure of oxygen [tex]O_{2}[/tex]
Put the values of pressures in above equation we get,
⇒ 736 = 46 + [tex]P_{O_{2} }[/tex]
⇒ [tex]P_{O_{2} }[/tex] = 736 - 46
⇒ [tex]P_{O_{2} }[/tex] = 690 torr
This is the value of the partial pressure of the oxygen.