Question

Helium is mixed with oxygen gas for deep-sea divers. Calculate the percent by volume of oxygen gas in the mixture if the diver has to submerge to a depth where the total pressure is 4.6 atm. The partial pressure of oxygen is maintained at 0.20 atm at this depth.

Answer 1

Answer:

Therefore the volume of oxygen gas is 4.35 % (approx).

Explanation:

The sum of the pressure of each gas is the total pressure of a mixture of gas.

$P_{Total}=P_1+P_2+....+P_n$

The partial pressure is a pressure of individual gas pressure.

Since the temperature and the numbers of moles of gas constant, then the ratio of volume percentage is equal to the ratio of pressure percentage.

$\frac{V_{O_2}}{V_{Total}} \times 100 \%= \frac{P_{O_2}}{P_{Total}}\times 100\%$

Here , $P_{O_2} = 0.20$ atm , $P_{Total}=4.6 \ atm$

$\frac{V_{O_2}}{V_{Total}} \times 100 \%= \frac{0.20}{4.6}\times 100 \%$

                    =4.35 %

Therefore the volume of oxygen gas is 4.35 % (approx).