Answer:
0.8894 is the probability that the test result comes back negative if the disease is present .
Step-by-step explanation:
We are given the following in the question:
P(Disco Fever) = P( Disease) =
[tex]P(D) = \dfrac{1}{2}\times 1\% = 0.5 \times 0.01 = 0.005[/tex]
Thus, we can write:
P(No Disease) =
[tex]P(ND) =1 - P(D)= 0.995[/tex]
P(Test Positive given the presence of the disease) = 0.99
[tex]P(TP | D ) = 0.99[/tex]
P( false-positive) = 4%
[tex]P( TP | ND) = 0.04[/tex]
We have to evaluate the probability that the test result comes back negative if the disease is present, that is
P(test result comes back negative if the disease is present)
By Bayes's theorem, we can write:
[tex]P(ND|TP) = \dfrac{P(ND)P(TP|ND)}{P(ND)P(TP|ND) + P(D)P(TP|D)}\\\\P(ND|TP) = \dfrac{0.995(0.04)}{0.995(0.04) + 0.005(0.99)} = 0.8894[/tex]
0.8894 is the probability that the test result comes back negative if the disease is present .