Answer:
Explanation:
Modulus of elasticity of brick, Y = 28 x 10^9 Pa
mass of each, m = 40 kg
Area of each, A = 0.5 m²
number of bricks, n = 4
height, h = 5 m
Let the change in height is Δh.
Use the formula of Modulus of elasticity
E = stress/ strain
stress = n x m x g/A = 4 x 40 x 9.8 / 0.5 = 3136 Pa
So,
[tex]3136 = 28 \times 10^{9}\times \frac{\Delta h}{5}[/tex]
Δh = 5.6 x 10^-7 m