Answer:
The value of mass flow rate from the turbine = 5.224 [tex]\frac{kg}{sec}[/tex]
Explanation:
Turbine entrance pressure = 10 M pa
Turbine entrance Temperature ( [tex]T_{1}[/tex] ) = 500 °c = 773 kelvin
Turbine outlet pressure = 10 k pa
Quality at exit = 0.9
Specific heat for the steam = 2.108 [tex]\frac{KJ}{kg k}[/tex]
From the steam table the temperature at pressure = 10 k pa of saturated liquid vapour steam is calculated. it is the exit temperature [tex]T_{2}[/tex].
⇒ Turbine exit Temperature ( [tex]T_{2}[/tex] ) = 46 °c = 319 kelvin
Power output of turbine ( [tex]W_{T}[/tex] )= 5 MW = 5000 KW
We know that Power output of turbine is given by [tex]W_{T}[/tex] = m × [tex]C_{}[/tex] × ( [tex]T_{2}[/tex] - [tex]T_{1}[/tex] )
Put all the values in the above formula we get,
⇒ 5000 = m × 2.108 × ( 773 - 319 )
⇒ m = 5.224 [tex]\frac{kg}{sec}[/tex]
This is the value of mass flow rate from the turbine.