Respuesta :

Answer:

  • -1 — does not cross
  • 0 — does not cross
  • 2 — crosses

Step-by-step explanation:

P(x) = x^4(x -2)^3(x +1)^2 has zeros at ...

  • -1 — multiplicity 2 (does not cross)
  • 0 — multiplicity 4 (does not cross)
  • 2 — multiplicity 3 (crosses)

The zeros that have even multiplicity are points where the graph does NOT cross the x-axis. This is true because an even power of a number does not change sign when the sign of the number changes.

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