Question

In a device like the one shown below, the mass of the cylinder is 8 kg and the cylinder falls a distance of 200 m. As a result, the temperature of the water increases by 4.2°C. What would the increase in temperature be if the mass of the cylinder were 16 kg?

Answer 1

Answer:

Increase in the temperature of water would be 8.4 degree C

Explanation:

As we know by energy conservation

Change in the gravitational potential energy of the cylinder = increase in the thermal energy of the water

Here we know that the gravitational potential energy of the cylinder is given as

$U = mgh$

here we have

m = 8 kg

h = 200 m

now we can say

$Mc\Delta T = (8 \times 9.8 \times 200)$

now if the mass of the cylinder is increase to 16 kg

then we have

$Mc\Delta T' = (16 \times 9.8 \times 200)$

now from above two equations

$\frac{\Delta T'}{\Delta T} = \frac{8}{16}$

$\Delta T' = 4.2 \times 2 = 8.4 Degree C$