Respuesta :
Answer: 300 joules
Explanation:The formula for specific heat is:
E
=
m
c
θ
, where:
E
is the energy needed in joules,
m
is the mass in kilograms,
c
is the specific heat,
θ
is the change in temperature, Celsius of Kelvin doesn't matter.
Here,
m
=
0.125
kg
c
=
480
J/kg
∘
C
θ
=
5
∘
C
, and inputting:
E
=
0.125
⋅
480
⋅
5
E
=
300
J
of energy is needed.
The amount of heat required to raise the temperature of Iron is 2245 J.
Given data:
The mass of iron is, m = 1 kg.
The initial temperature of iron is, [tex]T_{1} = 25^{\circ}\rm C[/tex].
The final temperature of iron is, [tex]T_{2} = 30^{\circ} \rm C[/tex].
The heat supplied to the iron will raise its temperature from initial to final point such that the unit degree rise in temperature per unit kg of mass will will give specific heat capacity of iron.
Then the expression for the heat required to raise the temperature of iron is,
[tex]Q=mc(T_{2}-T_{1})[/tex]
Here, c is the specific heat of iron.
Solving as,
[tex]Q=1 \times 449 \times (30-25)\\\\Q=2245 \;\rm J[/tex]
Thus, the amount of heat required to raise the temperature of Iron is 2245 J.
Learn more about the heat transfer here:
https://brainly.com/question/24985393