An aircraft, traveling northward, lands on a runway with a speed of 79 m/s. Once it touches down, it slows to 6.0 m/s over 785 m of runway. What is the average acceleration (magnitude and direction) of the plane during landing (in m/s2)? Take the positive direction to be northward.

Respuesta :

Answer:

[tex]-3.95m/s^2[/tex], South

Explanation:

We are given that

Initial speed of aircraft,u=79 m/s

Final speed of aircraft,v=6 m/s

Distance,s=785 m

[tex]v^2-u^2=2as[/tex]

Substitute the values

[tex](6)^2-(79)^2=2a(785)[/tex]

[tex]36-6241=1570a[/tex]

[tex]-6205=1570a[/tex]

[tex]a=-\frac{6205}{1570}=-3.95m/s^2[/tex]

Where negative sign indicates that the direction of acceleration is opposite to direction of motion.

Therefore, the direction of acceleration is south.

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