The probability that Team A wins and Team B loses is 0.112.
Given that,
Suppose Team A has a 0.75 probability to win their next game and Team B has a 0.85 probability to win their next game.
Assume these events are independent.
We have to determine,
What is the probability that Team A wins and Team B loses?
According to the question,
In an independent event and probability, the outcomes in an experiment are termed as events. Ideally, there are multiple events like mutually exclusive events, independent events, dependent events, and more.
Team A has a 0.75 probability to win their next game,
And Team B has a 0.85 probability to win their next game.
Therefore,
The probability that Team A wins and Team B loses is
[tex]\rm The \ probability \ of \ A \ wins \ and \ team \ B \ loses = Probability \ of \ team \ A winning \ game \times (1- Probability \ of \ team B \ lose \ the \ game)\\\\ The \ probability \ of \ A \ wins \ and \ team \ B \ loses = 0.75 \times (1-0.85)\\\\ The \ probability \ of \ A \ wins \ and \ team \ B \ loses =0.75 \times 0.15\\\\ The \ probability \ of \ A \ wins \ and \ team \ B \ loses =0.112[/tex]
Hence, The probability that Team A wins and Team B loses is 0.112.
For more details refer to the link given below.
https://brainly.com/question/743546
