Question

fter driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average mass of 69 kg per person. In addition, there are three 15-kg goats, five 3-kg chickens, and a total of 25 kg of bananas on their way to the market. Assume that the springs have somehow not yet compressed to their maximum amount. How much are the springs compressed

Answer 1

Answer:

The spring compressed is 0.44 m.

Explanation:

Given that,

Number of person = 25

Average Mass of each person $m_{p}= 25\times69 = 1725\ kg$

Mass of goat $m_{g}= 3\times15 = 45\ kg$

Mass of chicken $m_{c}= 5\times3 = 15\ kg$

Mass of bananas = 25 kg

If the spring constant is $4\times10^{4}\ N/m$

We need to calculate the total mass

$M=m_{p}+m_{g}+m_{c}+m_{b}$

Put the value in the formula

$M=1725+45+15+25$

$M=1810\ kg$

The weight of all these things is

$W=Mg$

$W=1810\times9.8$

$W=17738\ N$

We need to calculate the distance

Using formula of restoring force

$F=kx$

$x=\dfrac{F}{k}$

Put the value into the formula

$x=\dfrac{17738}{4\times10^{4}}$

$x=0.44\ m$

Hence, The spring compressed is 0.44 m.