What is the balanced chemical equation for the reaction used to calculate ΔH∘fΔHf∘ of BaCO3(s)BaCO3(s)? If fractional coefficients are required, enter them as a fraction (i.e. 1/3). Indicate the physical states using the abbreviation (ss), (ll), or (gg) for solid, liquid, or gas, respectively without indicating allotropes. Use (aqaq) for aqueous solution.

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Answer:

The balanced chemical equation for the solid barium carbonate used to calculate [tex]\Delta H^{o}_f[/tex]:

[tex]Ba(s)+C(s)+\frac{3}{2}O_2(g)\rightarrow BaCO_3(s)[/tex]

Explanation:

Enthalpy of formation ([tex]\Delta H_f[/tex]) is defined as change in enthalpy associated with formation of 1 mole of compound from its constituting elements present in their standard state.

The balanced chemical equation for the solid barium carbonate :

[tex]Ba(s)+C(s)+\frac{3}{2}O_2(g)\rightarrow BaCO_3(s)[/tex]

According to reaction, 1 mole of barium carbonate is formed from 1 mole of barium solid, 1 mole of carbon and 3/2 moles of oxygen gas.

The balanced chemical equation for the solid barium carbonate used to calculate the enthalpy of formation is:-

[tex]Ba(s)+C(s)+\frac{3}{2} O_2(g)\rightarrow BaCO_3(s)[/tex]

Enthalpy of formation(ΔH∘f):-It is defined as the enthalpy change associated with the production of one mole of compound from its constituent elements in their standard condition.

To calculate the enthalpy of formation, each component must be written in its standard condition in order to produce a reaction when one mole of product is formed.

The balanced chemical equation for the solid barium carbonate :

[tex]Ba(s)+C(s)+\frac{3}{2} O_2(g)\rightarrow BaCO_3(s)[/tex]

In the above reaction,  1 mole of barium solid, 1 mole of carbon, and 3/2 moles of oxygen gas are combined to form 1 mole of barium carbonate.

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