Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12โ€‹ pounds, and is spread evenly over the range ofโ€‹ possibilities, so that there is a uniform distribution. Find the probability that the given range of pounds lost is between 8 pounds and 11 pounds.

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Answer:

50% probability that the given range of pounds lost is between 8 pounds and 11 pounds.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between two values, c and d, in which d is greater than c, is given by the following formula:

[tex]P(c \leq X \leq d) = \frac{d-c}{b-a}[/tex]

Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12โ€‹ pounds

This means that [tex]a = 6, b = 12[/tex]

Find the probability that the given range of pounds lost is between 8 pounds and 11 pounds.

[tex]c = 8, d = 11[/tex]. So

[tex]P(8 \leq X \leq 11) = \frac{11-8}{12-6} = 0.5[/tex]

50% probability that the given range of pounds lost is between 8 pounds and 11 pounds.

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