Answer:
Change in volume on changing temperature from 33[tex]^{\circ}C[/tex] to 5[tex]^{\circ}C[/tex] is 5.49 mL
Explanation:
Initial volume of gas = V = 60 mL
Assuming final volume of gas to be V' mL
Initial temperature = T = 33[tex]^{\circ}C[/tex] = 306 K
Final temperature = T' = 5[tex]^{\circ}C[/tex] = 278 K
The relationship between volume and temperature of gas at constant pressure is shown below
[tex]\displaystyle \frac{V}{V'}=\displaystyle \frac{T}{T'} \\\displaystyle \frac{60\textrm{ mL}}{V'} = \displaystyle \frac{306\textrm{ K}}{T} \\V' = 54.51 \textrm{ mL} \\\textrm{Change in volume} = \left ( V-V' \right ) \\\textrm{Change in volume} = \left ( 60-54.51 \right )\textrm{ mL} \\\textrm{Change in volume} = 5.49 \textrm{ mL}[/tex]
Change in volume on changing temperature = 5.49 mL
