Answer:
a) Mean = 0.75
b) Standard error = 0.051
c) Yes
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 50
Sample proportion , p = 0.15
a) Mean
[tex]\mu = np = 50(0.15) = 7.5[/tex]
b) Standard error
[tex]S.E = \sqrt{\dfrac{p(1-p)}{n}} = \sqrt{\dfrac{0.15(1-0.15)}{50}} = 0.051[/tex]
c) Application of central limit theorem
Since the sample size is larger than 30, we cam apply central limit theorem for normal approximation.