Question

If the mathematical operation of division is performed on two numbers, the numerator having the units Joule-seconds (J-s) and the denominator having the units kilogram meter per second(kg m/s). Given a Joule by definition is a kg m2/s2, what units would the final answer have

Answer 1

Answer:

The final answer would have units of meters.

Explanation:

The unit at the numerator is J.s = kgm^2/s^2 × s = kgm^2/s

The unit at the denominator is kgm/s

Unit of final answer = unit at numerator ÷ unit at denominator = kgm^2/s ÷ kgm/s = kgm^2/s × s/kgm = m (meters)

Answer 2

Answer:

Result = m

Explanation:

Numerator = J.s

Denominator = kg.m/s

1 joule of energy is equal to 1 N.m

1 N.m force is equal to 1 kg.m/s²

so 1 joule is equal to 1 kg.m²/s²

Numerator = J.s = (kg.m²/s²).s = kg.m²/s

Denominator = kg.m/s

Result = Numerator/Denominator

Result = (kg.m²/s)/(kg.m/s) = (m²/s)/m/s = m²/m = m

Result = m