Question

The daily sales at a convenience store produce a normal distribution with a mean of $1,250 and a standard deviation of $125. The probability that the sales on a given day at this store are less than $1,310 is:

Answer 1

Answer:

0.6844 is the required probability.        

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $1,250

Standard Deviation, σ = $125

We are given that the distribution of daily sales is a bell like shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find

P(sales less than $1,310)

$P( x < 1310) = P( z < \displaystyle\frac{1310 - 1250}{125}) = P(z < 0.48)$

Calculation the value from standard normal z table, we have,  

$P(x < 1310) =0.6844= 68.44\%$

0.6844 is the probability that sales on a given day at this store are less than $1,310.

Answer 2

The probability that sales on a given day at this store are less than $1,310 is $68.44\%$

Probability:

It is given that, mean $\mu=1250$ and deviation $\sigma=125$

The z- score is given as,

                   $z-score=\frac{x-\mu}{\sigma} \\\\z=\frac{1310-1250}{125}=0.48$

We have to find probability that the sales on a given day at this store are less than $1,310

                $P(x < 1310)=P(z < 0.48)$

From z- value table.

           $P(x < 1310)=68.44\%$

The probability that sales on a given day at this store are less than $1,310 is $68.44\%$

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