Assume that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will experience which of the following?

a. No torque at all
b. A torque only if one magnetic pole is slightly closer to the charge than the other
c. A torque due to the charge attracting the south pole of the magnet
d. A torque due to the charge attracting the north pole of the manget

Assuming that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will not experience any torque at all - option A

Explanation:

Assuming that the length of the magnet is much smaller than the separation between it and the charge. As a result of magnetic interaction (i.e., ignore pure Coulomb forces) between the charge and the bar magnet, the magnet will not experience any torque at all; the reason being that: no magnetic field is being produced by a charge that is static. Only a moving charge can produce a magnetic effect. And the magnet can not have any torque due to its own magnetic lines of force.

andromache andromache · Answer 2 · 2022-03-01T15:45:39+01:00

The magnet will experience No torque at all.

Ignoring of pure Coulomb forces:

Here the length of the magnet should be less than the separation between it and the charge. Due to this there is magnetic interaction (i.e., ignore pure Coulomb forces) that lies between the charge and the bar magnet, the magnet should not experience any torque at all; the reason being that: no magnetic field should be generated via a charge i.e. here a moving charge can generate a magnetic effect. And the magnet can not have any torque because of its own magnetic lines of force.

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