Question

Determine the magnitude of the magnetic flux through the south-facing window of a house in British Columbia, where Earth's \overrightarrow{B} field has a magnitude of 5.8 × 10?5 T and the direction of \overrightarrow{B} field is 72? below horizontal with the horizontal component of\overrightarrow{B}field directed to the north. Assume the area of the window is 4.5 m^{2}

Question

Determine the magnitude of the magnetic flux through the west-facing window that has the same area.

Answer 1

Answer:

0

Explanation:

B = Magnetic field = $5.8\times 10^{-5}\ T$

A = Area of window = $4.5\ m^2$

$\theta$ =Angle of the magnetic field = $90^{\circ}$

Magnetic flux is given by

$\phi=BA\cos \theta\\\Rightarrow \phi=5.8\times 10^{-5}\times 4.5\times \cos 90^{\circ}\\\Rightarrow \phi=0\ Tm^2$

The magnitude of the magnetic flux through the west-facing window that has the same area is 0