One wire has a cross-sectional area of 1,250 cmil and a resistance of 7 ohms. A second piece of wire, identical except for cross-sectional area, has a resistance of 10 ohms. Determine what the cross-sectional area of this second wire is. (Cross-sectional area and resistance are inversely proportional.)

Respuesta :

Answer:

875 cmil

Explanation:

Cross section area of wire=[tex]A_1=1250 cmil[/tex]

Resistance of wire,[tex]R_1=7\Omega[/tex]

[tex]R_2=10\Omega[/tex]

We have to find the cross sectional area of second wire

We know that

[tex]R=\frac{\rho l}{A}[/tex]

According to question

[tex]l_1=l_2=l,\rho_1=\rho_2=\rho [/tex]

[tex]R_1=\frac{\rho l}{1250}[/tex]

[tex]7=\frac{\rho l}{1250}[/tex]....(1)

[tex]10=\frac{\rho l}{A}[/tex]...(2)

Equation (1) divided by equation (2) then, we get

[tex]\frac{7}{10}=\frac{A}{1250}[/tex]

[tex]A=\frac{7}{10}\times 1250=875cmil[/tex]

Hence, the cross- sectional area of second wire=875 cmil

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