Answer:
875 cmil
Explanation:
Cross section area of wire=[tex]A_1=1250 cmil[/tex]
Resistance of wire,[tex]R_1=7\Omega[/tex]
[tex]R_2=10\Omega[/tex]
We have to find the cross sectional area of second wire
We know that
[tex]R=\frac{\rho l}{A}[/tex]
According to question
[tex]l_1=l_2=l,\rho_1=\rho_2=\rho [/tex]
[tex]R_1=\frac{\rho l}{1250}[/tex]
[tex]7=\frac{\rho l}{1250}[/tex]....(1)
[tex]10=\frac{\rho l}{A}[/tex]...(2)
Equation (1) divided by equation (2) then, we get
[tex]\frac{7}{10}=\frac{A}{1250}[/tex]
[tex]A=\frac{7}{10}\times 1250=875cmil[/tex]
Hence, the cross- sectional area of second wire=875 cmil