Answer:
-1
Step-by-step explanation:
We evaluate [tex]\sin(2\pi+3\pi/2)[/tex]
In [tex]2\pi+3\pi/2[/tex], [tex]2\pi[/tex] is a complete revolution and is the same as 0. So we have
[tex]\sin3\pi/2 = \sin(\pi+\pi/2)[/tex]
One [tex]\pi[/tex] is a half revolution, putting the point at (-1, 0). [tex]\pi/2[/tex] is a quarter of a revolution. A quarter circle from (-1, 0) anticlockwise is (0, -1).
The sine is the y-coordinate of a point along a unit circle.
Hence, [tex]\sin(2\pi+3\pi/2)=-1[/tex]