Question

A good baseball pitcher can throw a baseball toward home plate at 93 mi/h with a spin of 1510 rev/min. How many revolutions does the baseball make on its way to home plate? For simplicity, assume that the 60 ft path is a straight line.

Answer 1

Answer:

$\Delta \theta =11.073\ rev$

Explanation:

Given,

Speed of baseball = 93 mi/h

spin = 1510 rev/min

$\Delta x = 60\ ft$

$v =93\times  \dfrac{88}{60} = 136.4 ft/s$

$\omega = 1510\times \dfrac{1}{60}= 25.167\ rad/s$

$\Delta t = \dfrac{\Delta x}{v}$

$\Delta t = \dfrac{60}{136.4 }$

$\Delta t = 0.44\ s$

Revolutions of ball

$\Delta \theta = \omega t$

$\Delta \theta = 25.167\times 0.44$

$\Delta \theta =11.073\ rev$

Revolution of the ball is equal to $\Delta \theta =11.073\ rev$.