Question

Coin Toss A coin is tossed upward with an initial velocity of 32 feet per second from a height of 16 feet above the ground.
The equation giving the object’s height h at any time t is h = 16 + 32t — 16tz Does the object ever reach a height of 32
feet?

Answer 1

Answer:

The object ever reach a height of 32  feet in 1 second

Step-by-step explanation:

The equation giving the object’s height : $h = 16 + 32t -16t^2$

Where h = object’s height

t = time

We are supposed to find Does the object ever reach a height of 32  feet

Substitute h = 32 in equation

$32 = 16 + 32t -16t^2$

$32-16= 32t -16t^2$

$16= 32t -16t^2$

$1=2t-t^2$

$t^2-2t+1=0$

$t^2-t-t+1=0$

$t(t-1)-(t-1)=0$

$(t-1)(t-1)=0$

$t=1,1$

So, The object ever reach a height of 32  feet in 1 second