Answer:
Length of other board [tex]=\frac{4x+20}{x^{2} -4}[/tex] metres
Step-by-step explanation:
Given: Length of board = [tex]\frac{7}{x-2}[/tex] metres
Length of board was divided into two.
Length of one piece = [tex]\frac{3}{x+2}[/tex] metres
Let [tex]l[/tex] = length of the other board
Length of the other board = Length of board - Length of one piece
So, [tex]l=\frac{7}{x-2}-\frac{3}{x+2}[/tex]
[tex]l=\frac{7(x+2)-3(x-2)}{(x-2)(x+2)} \\\\l=\frac{7x+14-3x+6}{x^{2} -4} \\\\l=\frac{4x+20}{x^{2} -4}[/tex]
Thus, length of the other board [tex]=\frac{4x+20}{x^{2} -4}[/tex] metres