Answer:
The magnitude of magnetic field at given point = [tex]5.33[/tex] × [tex]10^{-5}[/tex] T
Explanation:
Given :
Current passing through both wires = 5.0 A
Separation between both wires = 8.0 cm
We have to find magnetic field at a point which is 5 cm from any of wires.
From biot savert law,
We know the magnetic field due to long parallel wires.
⇒ [tex]B = \frac{\mu_{0}i }{2\pi R}[/tex]
Where [tex]B =[/tex] magnetic field due to long wires, [tex]\mu_{0} =[/tex] [tex]4\pi \times10^{-7}[/tex], [tex]R =[/tex] perpendicular distance from wire to given point
From any one wire [tex]R_{1} =[/tex] 5 cm, [tex]R_{2} =[/tex] 3 cm
so we write,
∴ [tex]B = B_{1} + B_{2}[/tex]
[tex]B = \frac{\mu_{0} i}{2\pi R_{1} } + \frac{\mu_{0} i}{2\pi R_{2} }[/tex]
[tex]B =\frac{ 4\pi \times10^{-7} \times5}{2\pi } [\frac{1}{0.03} + \frac{1}{0.05} ][/tex]
[tex]B = 5.33\times10^{-5} T[/tex]
Therefore, the magnitude of magnetic field at given point = [tex]5.33\times10^{-5} T[/tex]
