Question

A 55.0 kg ice skater is moving at 4.07 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole. She then moves in a circle of radius 0.808 m around the pole. (b) Compare this force with her weight by finding the ratio of the force to her weight.

Answer 1

Answer:

Explanation:

mass of ice skater, m = 55 kg

velocity, v = 4.07 m/s

radius, r = 0.808 m

The force is centripetal force, the formula for this force is

$F_{c}=\frac{mv^{2}}{r}$

$F_{c}=\frac{55\times 4.07\times 4.07}{0.808}$

Fc = 1127.56 N

Weight of the person, W = mg

W = 55 x 9.8 = 539 N

The ratio of force to he weight

$\frac{F_{c}}{W}=\frac{1127.56}{539}$= 2.09