Question

Four objects are situated along the y axis as follows: a1.96 kg object is at +2.90 m, a 2.98 kgobject is at +2.46 m, a 2.60 kg object is at the origin, and a3.99 kg object is at -0.503 m. Where is the center of mass of theseobjects?
x = m
y = m

Answer 1

Answer:

= + 2.27m

Explanation:

$y_c_m = \frac{m_1y_1 + m_2y_2 + m_3y_3 + m_4y_4}{y_1 +y_2+ y_3 +y_4}$

Given that,

mass (1) 1.96 kg object is at +2.90 m,

mass(2)  2.98 kgobject is at +2.46 m

mass(3) 2.60 kg object is at the origin

mass(4) 3.99 kg object is at -0.503 m

$y = \frac{(1.96 \times 2.90)+ (2.98 \times2.46) + (2.60 \times 0)- (3.99\times0.503) }{2.90 + 2.46 + 0 - 0.503}$

$= \frac{11.00783}{4.857}$

= 2.27m