Question

what is the equation for points (-2,-4) and (4,-1) ?

Answer 1

Answer:

$y=\frac{1}{2}x-3$

Step-by-step explanation:

The question is

Find the equation of the line for points (-2,-4) and (4,-1)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

(-2,-4) and (4,-1)

substitute

$m=\frac{-1+4}{4+2}$

$m=\frac{3}{6}$

$m=\frac{1}{2}$

step 2

Find the equation if the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{1}{2}$

$point\ (4,-1)$

substitute

$y+1=\frac{1}{2}(x-4)$

step 3

Convert to slope intercept form

$y=mx+b$

we have

$y+1=\frac{1}{2}(x-4)$

isolate the variable y

$y+1=\frac{1}{2}x-2$

$y=\frac{1}{2}x-2-1$

$y=\frac{1}{2}x-3$