Assume that a specific hard disk drive has an average access time of 16ms (i.e. the seek and rotational delay sums to 16ms) and a throughput or transfer rate of 185MBytes/s, where a megabyte is measured as 1024.

Required:
What is the average access time for a hard disk spinning at 360 revolutions per second with a seek time of 10 milliseconds?

Respuesta :

Answer:

Average access time for a hard disk = 11.38 ms

Explanation:

See attached pictures for step by step explanation.

Ver imagen abdullahfarooqi
Ver imagen abdullahfarooqi
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