Respuesta :
Answer:
def find_max(num_1, num_2):
max_val = 0.0
if(num_1 > num_2):
max_val = num_1
else:
max_val = num_2
return max_val
max_sum = 0.0
num_a = float(input())
num_b = float(input())
num_y = float(input())
num_z = float(input())
max_sum = find_max(num_a,num_b)+find_max(num_y,num_z)
print('max_sum is:',max_sum)
Explanation:
def find_max(num_a, num_b) :
# define a function named find_max
max_num = 0.0
# initialize maximum number, max_num to 0
if num_a > num_b :
#checks if num_a is greater than num_b
max_num = num_a
#if condition is true, set num_a as max_num
else :
max_num = num_b
#if otherwise, set num_b as max_num
Get user inputs :
num_a = eval(input())
num_b = eval(input())
num_c = eval(input())
num_d = eval(input())
#num_a, num_b, num_c and num_d takes input from user.
max_sum = find_max(num_a, num_b) + find_max(num_c, num_d)
#call the find_max function twice passing the input values as argument
print("max_sum is:", max_sum)
#Display the value of max_sum
Program written in python(3) :
We defined a function find_max to obtain the greater value of any two numbers
- Using the find_max function, we take 4 user inputs.
- Then we use the find_max function on the inputs, taking 2 inputs at a time.
- Then we use the addition operator to take the sum of each maximum output.
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