Please solve and explain how. Photo attached
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Answer:
Step-by-step explanation:
[tex]\frac{2}{k^2-2k}=1-\frac{1}{k^2-2k}[/tex]
multiply by [tex]\frac{k^2-2k}{1}[/tex] on each side
[tex]2=k^2-2k-1[/tex]
add 1 on both sides [tex]3=k^2-2k[/tex]
make it equal 0
[tex]0=k^2-2k-3[/tex]
Factor
[tex](k-3)(k+1)[/tex]
answer is 3 and -1