Question

Triangle XYZ is shown on the coordinate plane below:

Triangle XYZ on the coordinate plane with ordered pairs at X 4, 5, at Y 5, 3, at Z 1, 3

If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', what is the ordered pair of X'?

Answer 1

The new ordered pair would be X= -4,5

Answer 2

Answer:

The ordered pair of X' are 4, -3.

Step-by-step explanation:

Since, the rule of reflection across a line y = p is,

$(x,y)\rightarrow (x,2p-y)$

Here, the triangle XYZ is reflected across the line y = 1 and create the triangle X'Y'Z',

That is, p = 1,

Thus, the rule of reflection would be,

$(x,y)\rightarrow (x, 2-y)$

Also, the coordinates of X are (4,5),

So, after reflection,

$(4,5)\rightarrow (4, 2-5)$

Hence, the coordinates of X' are (4, -3).