Answer:
kp = 1.55
Explanation:
To get to this reaction, we just need to sum the other two reactions, and multiply coefficients if it's needed so:
C(s) + 2H₂O(g) ⇄CO₂(g) + 2H₂(g) Kp1 = 3.23 (1)
H₂(g) + CO₂(g) ⇄ H₂O(g) + CO(g) Kp2 = 0.601 (2)
we will multiply eqn 2 by 2 because we need to eliminate H₂
2H2(g) + 2CO2(g) ⇄ 2H2O(g) + 2CO(g) Kp = (0.601)²
Now, add both equation
C(s) + 2H₂O(g) ⇄CO₂(g) + 2H₂(g) Kp1 = 3.23
2H2(g) + 2CO2(g) ⇄ 2H2O(g) + 2CO(g) Kp = (0.601)²
we have,
C(s) + CO₂(g) ⇄ 2CO(g)
Now the value of Kp will be:
kp = 3.23 × (0.693)²
kp = 1.55