Carbon absorbs energy at a wavelength of 150. nm. The total amount of energy emitted by a carbon sample is J. Calculate the number of carbon atoms present in the sample, assuming that each atom emits one photon.

Respuesta :

The given question is incomplete. The complete question is as follows.

Carbon absorbs energy at a wavelength of 150 nm. The total amount of energy emitted by a carbon sample is [tex]1.93 \times 10^{5} J[/tex]. Calculate the number of carbon atoms present in the sample, assuming that each atom emits one photon.

Explanation:

It is given that the energy at which C-atom absorbs energy is 150 nm. So, energy emitted by the carbon atom will have same wavelength at which C-atom absorbs the energy.

As we know that relation between energy and wavelength is as follows.

                  E = [tex]\frac{hc}{\lambda}[/tex]

where,  h = Planck's constant = [tex]6.624 \times 10^{-34} J sec[/tex]

             c = speed of light = [tex]3 \times 10^{8} m/s[/tex]

             [tex]\lambda[/tex] = 150 nm = [tex]150 \times 10^{-9}[/tex]

Therefore, energy of one carbon atom is calculated as follows.

                E = [tex]\frac{hc}{\lambda}[/tex]

                  = [tex]\frac{6.624 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{150 \times 10^{-9}}[/tex]

                 = [tex]1.324 \times 10^{-18} J[/tex]

As the total energy emitted by the carbon sample is  [tex]1.93 \times 10^{5} J[/tex]. Let us assume that the number of C-atoms in the sample be x and it is calculated as follows.

           [tex]E_{total} = n \times E_{1C-atom}[/tex]

                     n = [tex]\frac{E_{total}}{E_{1C-atom}}[/tex]

                        = [tex]\frac{1.93 \times 10^{5}}{1.324 \times 10^{-18} J}[/tex]

                        = [tex]1.45 \times 10^{23}[/tex]

Thus, we can conclude that number of carbon atoms present in the sample, are [tex]1.45 \times 10^{23}[/tex].