Respuesta :
Answer:
[tex]F = m \cdot x \cdot g[/tex]
Explanation:
The centrifugal net force experimented by driver is:
[tex]F = m \cdot \frac{v^{2}}{R}[/tex]
Let make the following consideration:
[tex]\frac{v^{2}}{R} = x \cdot g\\v^{2} = x \cdot g \cdot R[/tex]
After a quick substitution and some algebraic handling, the following expression is formed:
[tex]F = m \cdot x \cdot g[/tex]
The magnitude of the net force on the driver during the turn is equal to the apparent weight of the driver = xmg.
The given parameters;
- speed of the car, = v
- mass of the driver, = m
- Weight of the driver = x
The actual weight of the driver is calculated as;
W = mg
The apparent weight of the driver is given as;
Fₙ = xmg
The frictional force between the driver and the curve road = 0
At constant speed, acceleration = 0
The magnitude of the net force on the driver during the turn is equal to the apparent weight of the driver = xmg.
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