Question

Mg(OH)2 in the form of Milk of Magnesia is used to neutralize excess stomach acid. Mg(OH)2 58.33 11. How many moles of stomach acid can be neutralized by 1.00 g of Mg(OH)2

Answer 1

Answer:

0.03429 mole

Explanation:

The type of acid present in the stomach is hydrochloric acid (HCl).

From the balanced equation:

$Mg(OH)_2 + 2HCl --> MgCl_2 + 2H_2O$

2 moles of HCl requires 1 mole of Mg(OH)2 fro complete neutralization.

moles of Mg(OH)2 present in 1g = mass/molar mass

                                                            = 1/58.33 = 0.01714 mole

If 1 mole of Mg(OH)2 is needed for 2 moles of HCl, then

0.01714 mole of Mg(OH)2 will require: 2 x 0.01714 moles HCl

= 0.03429 mole of HCl

Hence, 0.03429 mole of stomach acid can be neutralized by 1.00g of Mg(OH)2