Question

The coefficient of performance of a residential heat pump is 1.6. Calculate the heating effect in kJ/s this heat pump will produce when it consumes 4 kW of electrical power.

Answer 1

Answer:

$Q_{H}=6.4kJ/s$

Explanation:

Given data

Coefficient of performance of a residential heat pump=1.6

Electrical power P=4kW

Required

Heat Q

Solution

The rate of heat produced is given as

$Q_{H}=COP_{HP}Win$

Substitute the given values

So

$Q_{H}=4kW*1.6\\Q_{H}=6.4kJ/s$