Question

In a particular experiment, the partial pressures of H 2 and I 2 at equilibrium are 0.710 and 0.888 atm, respectively. The partial pressure of HI is __________ atm.

Answer 1

This is an incomplete question, here is a complete question.

Kp = 0.0198 at 721 K for the reaction:

$2HI(g)\rightleftharpoons H_2(g)+I_2(g)$

In a particular experiment, the partial pressures of H₂ and I₂ at equilibrium are 0.710 and 0.888 atm, respectively. The partial pressure of HI is __________ atm.

Answer : The partial pressure of HI is, 5.64 atm

Explanation :

For the given chemical reaction:

$2HI(g)\rightleftharpoons H_2(g)+I_2(g)$

The expression of $K_p$ for above reaction follows:

$K_p=\frac{P_{H_2}\times P_{I_2}}{(P_{HI})^2}$

We are given:

$P_{H_2}=0.710atm$

$P_{H_2}=0.888atm$

$k_p=0.0198$

Now put all the given values in above equation, we get:

$0.0198=\frac{0.710\times 0.888}{(P_{HI})^2}$

$P_{HI}=5.64atm$

Thus, the partial pressure of HI is, 5.64 atm