Question

The yield in pounds from a day's production is normally distributed with a mean of 1500 pounds and standard deviation of 100 pounds. Assume that the yields on different days are independent random variables. Round the answers to 3 significant digits. (a) What is the probability that the production yield exceeds 1500 pounds on each of five days next week

Answer 1

It appears that the question is incomplete but the answer to the part given is as below.

Answer:

(a) 0.0313

Step-by-step explanation:

In a normal distribution curve, the mean divides the curve into two equal parts. Hence, the probability of being lesser or higher than the mean is 1/2. This is the probability for a single day.

From the question, the probability of a day is independent of that of another day. For 5 days, the probability is

$(\frac{1}{2})^5 = 0.5^5 = 0.03125 = 0.0313$ to 3 significant digits.