Answer: 9.59° and 350.41°
Explanation: The formulae that relates the force F exerted on a moving charge q with velocity v in a magnetic field of strength B is given as
F =qvB sin x
Where x is the angle between the strength of magnetic field and velocity of the charge.
q = 1.609×10^-19 C
v = 4×10³ m/s
B = 1.25 T
F = 1.40×10^-16 N
By substituting the parameters, we have that
1.40×10^-16 = 1.609×10^-19 × 4×10³ × 1.25 × sinx
sin x = 1.40×10^-16/ 1.609×10^-19 × 4×10³ × 1.25
sin x = 1.40×10^-16 /8.045*10^(-16)
sin x = 0.1666
x = 9.59°
The value of sin x is positive in first and fourth quadrant.
Hence to get the second value of x, we move to the 4th quadrant of the trigonometric quadrant which is 360 - x
Hence = 360 - 9.59 = 350.41°
