ball of mass 0.4 kg is attached to the end of a light stringand whirled in a vertical circle of radius R = 2.9 m abouta fixed point. Find the magnitude of the tension when themass is at the top if its speed at the top is 8.5 m/s.(

Respuesta :

Answer:

[tex]6.046N[/tex]

Explanation:

The net force exerted on the mass is the sum of tension force and the external force of gravity.

[tex]F_n_e_t=F_g+F_t[/tex]

[tex]F_t[/tex] is the tension force.[tex]F_g=9.8N/kg[/tex] is the force of gravity.

[tex]F_n_e_t=ma_c=mv^2/r\\[/tex]

where [tex]r[/tex] is the rope's radius from the fixed point.

From the net force equation above:

[tex]F_t=F_n_e_t-F_g\\=mv^2/r-mg\\=0.4\times(8.5^2/2.9)-0.4\times9.8\\=6.046N[/tex]

Hence the tension force is 6.046N