Question

A constant voltage of 8.00 V has been observed over a certain time interval across a 2.30 H inductor. The current through the inductor, measured as 1.00 A at the beginning of the time interval, was observed to increase at a constant rate to a value of 8.00 A at the end of the time interval. How long was this time interval

Answer 1

Answer:2.01 s

Explanation:

Given

Applied voltage $V=8\ V$

Inductance $L=2.3\ H$

Change in Current $\Delta i=8-1=7\ A$

Induced EMF is given by

$V=L\times \dfrac{\Delta A}{\Delta t}$

$8=2.3\times \dfrac{7}{\Delta t}$

$\Delta t=\dfrac{2.3\times 7}{8}$

$\Delta t=2.0125\ s$