Question

A family is selected at random from the city. Find the probability that the size of the family is between 2 and 5 inclusive. Round approximations to three decimal places.

Answer 1

Answer:

$P(2 \leq X \leq 5)$

And using the table from the info we got:

$P(2 \leq X \leq 5) = P(X=2) +P(X=3) +P(X=4)+P(X=5)$

And replacing we got:

$P(2 \leq X \leq 5) =0.464+0.212+0.197+0.078= 0.951$

Step-by-step explanation:

For this case we assume that following  table shows the distribution of family size in a certain U.S. city

Family Size Probability

 2                  0.464

 3                  0.212

 4                  0.197

 5                  0.078

 6                  0.030

 7+                0.019

We assume that X represent the random variable "family size"

And for this case we want to find this probability:

$P(2 \leq X \leq 5)$

And using the table from the info we got:

$P(2 \leq X \leq 5) = P(X=2) +P(X=3) +P(X=4)+P(X=5)$

And replacing we got:

$P(2 \leq X \leq 5) =0.464+0.212+0.197+0.078= 0.951$