Answer:
5278.0
21112
2927
Step-by-step explanation:
P = Po[2^(t/5)]
8000 = Po(2^⅗)
Po = 5278.0
P = 5278(2^(10/5))
P = 21112
P = Po[2^(t/5)]
ln(P/Po) = (t/5)ln2
ln(P) - ln(Po) = (t/5)ln2
1/P . dP/dt = ln2/5
dP/dt = P(ln2)/5
At t = 10, P = 21112
dP/dt = 2927