Answer:
Explanation:
Give that
I=16A
The current is flowing to the right
Equal amount of positive and negative charges.
i.e, total charge is q= Q+Q=2Q. i.e magnitude
Then, the rate of charge that pass though is dq/dt
Give that,
q=it
2Q=it
Let differentiate with respect to t
2dQ/dt=i
Then, dQ/dt=i/2
Since i=16A
Then, dQ/dt=16/2
dQ/dt= 8 A/s. Toward the left